std::is_literal_type
Defined in header <type_traits>
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template< class T > struct is_literal_type; |
(since C++11) (deprecated in C++17) (removed in C++20) |
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If T
satisfies all requirements of LiteralType, provides the member constant value
equal true. For any other type, value
is false.
The behavior is undefined if std::remove_all_extents_t<T> is an incomplete type and not (possibly cv-qualified) void.
Template parameters
T | - | a type to check |
Helper variable template
template< class T > inline constexpr bool is_literal_type_v = is_literal_type<T>::value; |
(since C++17) (deprecated) (removed in C++20) |
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Inherited from std::integral_constant
Member constants
value [static] |
true if T is a literal type , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator() (C++14) |
returns value (public member function) |
Member types
Type | Definition |
value_type
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bool
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type
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std::integral_constant<bool, value> |
Notes
Only literal types may be used as parameters to or returned from constexpr functions. Only literal classes may have constexpr member functions.
Example
Run this code
#include <iostream> #include <type_traits> struct A { int m; }; struct B { virtual ~B(); }; int main() { std::cout << std::boolalpha; std::cout << std::is_literal_type<A>::value << '\n'; std::cout << std::is_literal_type<B>::value << '\n'; }
Output:
true false